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Sagot :
Answer:
[tex]M.M=150.8g/mol[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly possible for us to set up the equation for the freezing point depression as shown below:
[tex]\Delta T=-i*m*Kf[/tex]
Thus, given Kf, i (equal to 1 because it is nonelectrolyte) and the freezing point depression, we can now calculate the molality of the solution:
[tex]m=\frac{\Delta T}{-i*Kf}=\frac{-0.84\°C}{-1*4.9\°C/m}\\\\m=0.17mol/kg[/tex]
Next, we calculate the kilograms of solvent by dividing the 200 g by 1000 to get 0.200 kg and thus calculate the moles of the solute X:
[tex]n_X=0.200kg*0.171mol/kg\\\\n_X=0.0343mol[/tex]
Finally, the molar mass by dividing the grams by moles:
[tex]M.M=\frac{5.17g}{0.0343mol}\\\\M.M=150.8g/mol[/tex]
Regards!
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