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Calculate the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water at a depth of 380 m. (Assume the water's mass density at this depth is 1000 kg/m3k.)

Sagot :

Answer:

Explanation:

Hydrostatic pressure due to a water column of height  h can be given by the following expression.

P = hρg

where ρ is density of water and g is acceleration due to gravity .

Substituting the values.

P = 380 x 1000 x 9.8

= 3.72 x 10⁶ Pa.

Answer:

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Explanation:

Given that,

The density of water, d = 1000 kg/m³

Depth, h = 380 m

We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :

[tex]P=\rho gh[/tex]

Put all the values,

[tex]P=1000\times 9.8\times 380\\\\P=3.72\times 10^6\ Pa[/tex]

Force exerted,

F = P/A

So,

[tex]F=\dfrac{3.72\times 10^6\ Pa}{A}\ N[/tex]

Where

A is the area of crosss section

Hence, this is the required solution.

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