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Sagot :
Answer:
:)
Step-by-step explanation:
[tex]\frac{4x^2 - 1}{(x+4)(2x-1)} = \frac{(2x)^2 - (1)^2}{(x+4)(2x-1)}[/tex]
[tex]=\frac{(2x-1)(2x+1)}{(x+4)(2x-1)}\\\\=\frac{2x+1}{x+4}[/tex]
Answer:
i don't know
Step-by-step explanation:
it is very hard
sorry !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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