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A car leaves for the trip at 8:07 pm and travels 30 km north on highway 59 and then remembers they forgot
something when they stopped and has to go back 10 km south and then
continues their trip for 80 km north. They arrive at 9:30 for their trip.
Calculate their average speed.
Calculate their average velocity.
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Sagot :

ayomidemathins72

[tex]velocity = \frac{distance}{time} [/tex]

[tex] \frac{(30 + 10 + 80) \times 1000}{83 \times 60} [/tex]

[tex] = 0.024m.{s}^{ - 1} [/tex]

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