Answered

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when
[tex] {x}^{3} + a {x}^{2} + 5x + 3[/tex]
is divided by
[tex]x + 2[/tex]
the remainder is b. Determine the value of b​

Sagot :

swiler

x³ + ax² + 5x + 3. x + 2 = 0

x = -2

(-2)³ + a(-2)² + 5(-2) + 3 = 0

-8 + 4a - 10 + 3 = 0

4a - 15 = 0

4a = 15

a = 15/4

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