Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Darcy suffers from farsightedness equally severely in both eyes. The focal length of either of Darcy's eyes is 19.8 mm in its most accommodated state (i.e, when the eye is focusing on the closest object that it can clearly see) What lens strength (a.k.a., lens power) of contact lenses should be prescribed to correct the farsightedness in Darcy's eyes? (Assume the lens-to retina distance of Darcy's eyes is 2.00 cm, and the contact lenses are placed a negligibly small distance from the front of Darcy's eyes)
i. 1.64D
ii. 2.98 D
iii. 2.19 D
iv. 3.49 D
v. 1.37 D

Sagot :

Answer:

Explanation:

Power of defective eye = (1 / near point )+ (1 / lens-retina distance )

1 / .0198 m  =  (1 / near point )+ (1 / .02 m  )

= 50.50 = (1 / near point )+ 50

0.50 = 1 / near point

near point = 1 / .5 = 2m

= 200 cm .

for near point at 25 cm , convex lens will be required.

u = - 25 cm , v = - 200 cm ,

1 / v - 1 / u = 1 /f for lens

- 1 / 200 +  1 / 25 = 1 / f

= .04 - .005 = 1 /f

.035 = 1 / f

f = 28.57 cm = 0.2857 m

power = 1 /f

= 1 / 0.2857

= 3.5 D .

i v ) option is correct .

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.