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Sagot :
Answer:
4/28 (simplified to 1/7)
Step-by-step explanation:
Given:
- There are 28 total students in the class
- 9 of them play basketball
- 17 of them play baseball
- 6 of them play neither sport
Question:
What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Answer:
- Because we know there are 28 total students in the class and 6 play neither basketball nor baseball, then there are 28-6 = 22 students who either play ONLY basketball, ONLY baseball, or both
- We know that 9 out of the 22 play basketball and 17 out of the 22 play baseball
- Therefore, 22-9 = 13 students play ONLY basketball, and 22-17 = 5 students play ONLY baseball
- This means that the amount of students that play BOTH basketball and baseball is 22-(13+5) = 22-18 = 4 students
- Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is 4/28 or 1/7
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