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Sagot :
Answer:
I = 2.667 kg m²
Explanation:
The moment of inertia of a body can be calculated by the expression
I = ∫ L² dm
For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is
I = [tex]\frac{1}{12}[/tex] m L²
let's calculate
I = [tex]\frac{1}{12}[/tex] 2 4²
I = 2.667 kg m²
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