Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back and forth in the breeze once every
T = 6.2 seconds.Randomized VariablesT = 6.2 seconds(a) Calculate the frequency of oscillation (in Hertz) of the chandelier.(b) Calculate the angular frequency ω of the chandelier in radians/second.
(c) Determine the length L in meters of the chandelier. sig.gif?
(d) That evening, while hanging out in J.J. Thompson’s House O’ Blues, you notice that (coincidentally) there is a chandelier identical in every way to the one at the Michelson exhibit except this one swings back and forth 0.11 seconds slower, so the period is T + 0.11 seconds. Determine the acceleration due to gravity in m/s2 at the club.

Sagot :

okpalawalter8

Answer:

a)  [tex]F=0.16Hz[/tex]

b)  [tex]\omega=1rad/s[/tex]

c)  [tex]L=9.54m[/tex]

d)  [tex]g=9.46m/s^2[/tex]

Step-by-step explanation:

From the question we are told that:

Time [tex]T =6.2[/tex]

a)

Generally the equation for Frequency F is mathematically given by:

 [tex]F=\frac{1}{T}[/tex]

 [tex]F=\frac{1}{6.2}[/tex]

 [tex]F=0.16Hz[/tex]

b)

Generally the equation for Frequency F is mathematically given by:

 [tex]\omega=2\pi f[/tex]

 [tex]\omega=2*314* 0.16[/tex]

 [tex]\omega=1rad/s[/tex]

c)

Generally the equation for Length of Chandelier L is mathematically given by:

Since

 [tex]T=2*3.142\sqrt{\frac{L}{g}}[/tex]

Therefore

 [tex]L=\frac{gT^2}{4 \pi^2}[/tex]

 [tex]L=\frac{9.8*(6.2)^2}{4 \pi^2}[/tex]

 [tex]L=9.54m[/tex]

d)

Since

Michelson exhibit except this one swings back and forth 0.11 seconds slower

Therefore

 [tex]T'=T+0.11[/tex]

 [tex]T'=6.31[/tex]

Generally the equation for acceleration due to gravity g is mathematically given by:

 [tex]g = \frac{4\pi ^2L}{( T')}^2[/tex]

 [tex]g = \frac{4\pi ^2L\*9.54}{( 6.31 s )}^2[/tex]

 [tex]g=9.46m/s^2[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.