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Sagot :
Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Explanation:
Given: [tex]V_{1}[/tex] = ?, [tex]M_{1}[/tex] = 0.55 M
[tex]V_{2}[/tex] = 100.0 mL, [tex]M_{2}[/tex] = 2.50 M
Formula used to calculate the volume of KBr is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL[/tex]
Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
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