fernandgarxs12y13
Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

How many atoms are in a 1.8 mol sample of Magnesium (Mg)?

Sagot :

Space

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

Atomic Structure

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 1.8 mol Mg

[Solve] atoms Mg

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:                                                                                                       [tex]\displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})[/tex]
  2. [DA] Multiply [Cancel out units]:                                                                      [tex]\displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

Answer:  1.0836 * 10^24 atoms

This value is approximate

===========================================================

Explanation:

1 mole = 6.02*10^23 atoms approximately

This applies to any element.

Multiply both sides by 1.8 and we get...

1 mole = 6.02*10^23 atoms

1.8*1 mole = 1.8*6.02*10^23 atoms

1.8 mole = 10.836*10^23 atoms

1.8 mole = (1.0836*10)*10^23 atoms

1.8 mole = 1.0836 * 10^(1+23)

1.8 mole = 1.0836 * 10^24 atoms

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.