Answered

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A chemical reaction done at STP conditions is supposed to produce 0.011 moles of CO2 gas. How many liters of gas will that be?

Sagot :

sebassandin

Answer:

V = 0.24 L.

Explanation:

Hello there!

In this case, it is possible to approach this problem by using the ideal gas equation defined by:

[tex]PV=nRT[/tex]

Whereas our unknown is V, volume, and we solve for it as follows:

[tex]V=\frac{nRT}{P}[/tex]

Then since the STP conditions are ate 273.15 K and 1 atm, the volume of 0.011 moles of CO2 gas turns out to be:

[tex]V=\frac{0.011mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=0.24L[/tex]

Regards!

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