Hi there!
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I believe your answer is:
Option A; [tex]m \leq\frac{3}{5}[/tex]
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Here’s why:
- We can use inverse operations to solve for 'm'.
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[tex]\boxed{\text{Solving for 'm':}}\\\\5m+1\leq4\\--------\\\rightarrow 5m + 1 - 1 \leq 4 - 1\\\\\rightarrow 5m\leq3\\\\\rightarrow \frac{5m\leq3}{5}\\\\\rightarrow \boxed{m\leq\frac{3}{5}}[/tex]
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Any number that is less than or equal to the value of three-fifths would work.
The option that is less than or equal to (3/5) is option A.
Assuming that there are more options than the options shown, choose the numbers that are less than or equal to (3/5).
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Hope this helps you. I apologize if it’s incorrect.
