Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0
(3,1), r = /6
(-3,-1), r = /6
(3,1) r = 6
(9,1), r = 36

Sagot :

msm555

Answer:

Solution given:

the equation of a circle is:

x²+y²-6x-2y+4=0

x²-2*x*3+3²+y²-2y+1²-1²+4=0

(x-3)²+(y-1)²=9+1-4

(x-3)²+(y-1)²=6

comparing above equation with

(a-h)²+(y-k)²=r²

we get

centre (h,k)=(3,1)

radius=√6

option first

(3,1), r = √6 is a required answer.

sammonkey0704

Answer:

(3,1), r = √6 is a required answer.

Step-by-step explanation:

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.