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The length of a rectangle is 16 units more than it's with. The area of the rectangle can be expressed as x^4 - 64.

Sagot :

Answer:

[tex]Width = x^2 - 8[/tex]

Step-by-step explanation:

Given

[tex]L = 16 + W[/tex]

[tex]Area = x^4 - 64[/tex]

Required

An expression for the width

We have:

[tex]Area = x^4 - 64[/tex]

Express as difference of two squares:

[tex]Area = (x^2 + 8)(x^2 - 8)[/tex]

For all acceptable values of x,

[tex]x^2 + 8>x^2 - 8[/tex]

So:

[tex]Length = x^2 + 8[/tex]

[tex]Width = x^2 - 8[/tex]