At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

HelpppppPpapPPapPapp


HelpppppPpapPPapPapp class=

Sagot :

Step-by-step explanation:

we have two lines you have to draw.

one is all in the bottom left quadrant (for x<=0) and one in the upper right quadrant (for x>5).

the easiest is for x>5. the line function is only

f(x) = y = 3

so, this is a horizontal line on the grid line for y = 3. it starts above x=5 and then goes all the way to the right ("to infinity and beyond !"). just, if possible, mark the starting point at x=5 as a little empty "circle" instead of a full dot, as x=5 is explicitly excluded (due to x>5).

and for x<=0 the line

f(x) = y = 4x - 3

goes sharp down but goes a little bit to the left the further down it goes. it starts with x=0, which gives y=-3 per the function.

so, the starting point (with a full dot, as x=0 is included) is (0,-3).

from there it goes sharp down and a little bit to the left.

for example the next point is for x=-1, which gives y=-7, so it is the point (-1,-7). x=-2 gives y=-11 and the point (-2,-11).

the line has to go through so these points and further down (again, "to infinity and beyond !"), as to move further left on the negative x-axis.