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Find the value of x. Round to the nearest. ​

Find The Value Of X Round To The Nearest class=

Sagot :

msm555

Answer:

Solution given:

perpendicular [P]=x

base[B]=9

hypotenuse [H]=41

Now.

By using Pythagoras law

H²=P²+B²

41²=x²+9²

x²=41²-9²

x=[tex]\sqrt{1600}=40[/tex]

x=40 is a required answer.