Answered

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Which equation has the following: Center (0, -3) and radius [tex]\sqrt{11}[/tex]

Sagot :

Answer:

The equation of the circle is [tex]x^2 + (y + 3)^2 = 11[/tex]

Step-by-step explanation:

Equation of a circle:

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

Center (0, -3)

This means that [tex]x_0 = 0, y_0 = -3[/tex]

Radius square root of 11

This means that [tex]r = \sqrt{11}[/tex]

Equation of the circle:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

[tex](x - 0)^2 + (y - (-3))^2 = (\sqrt{11})^2[/tex]

[tex]x^2 + (y + 3)^2 = 11[/tex]

The equation of the circle is [tex]x^2 + (y + 3)^2 = 11[/tex]

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