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In ΔJKL, the measure of ∠L=90°, JL = 80, KJ = 89, and LK = 39. What is the value of the sine of ∠J to the nearest hundredth

Sagot :

Given:

In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.

To find:

The value of sine of ∠J.

Solution:

In a right angle triangle,

[tex]\sin\theta =\dfrac{Perpendicular}{Hypotenuse}[/tex]

In triangle JKL,

[tex]\sin J =\dfrac{LK}{KJ}[/tex]

[tex]\sin J =\dfrac{39}{89}[/tex]

[tex]\sin J =0.4382[/tex]

[tex]\sin J \approx 0.44[/tex]

Therefore, the value of sine of ∠J is about 0.44.

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