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Write the equation in slope-intercept form of the line that includes the point (3,2) and has a slope of 4/3.

Write The Equation In Slopeintercept Form Of The Line That Includes The Point 32 And Has A Slope Of 43 class=

Sagot :

akposevictor

Answer:

[tex] y = \frac{4}{3}x - 2 [/tex]

Step-by-step explanation:

Given:

Slope (m) = ⁴/3

Point on the line = (x, y) = (3, 2)

Required:

Write the equation in slope-intercept form which is y = mx + b

Solution:

Since we know the slope(m), we need to find the y-intercept (b).

This, substitute (x, y) = (3, 2) and m = ⁴/3 into y = mx + b, and solve for b. Thus:

2 = ⁴/3(3) + b

2 = 4 + b

2 - 4 = b

-2 = b

b = -2

To write the equation, substitute m = ⁴/3 and b = -2 into y = mx + b

[tex] y = \frac{4}{3}x - 2 [/tex]

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