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Sagot :
Answer: If you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
Explanation:
The given reaction equation is as follows.
[tex]2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}[/tex]
Here, 6 moles of HCl reacts with 2 moles of [tex]AlCl_{3}[/tex]. This means that 1 mole of [tex]AlCl_{3}[/tex] is obtained as follows.
[tex]\frac{6}{2} HCl\\= 3 HCl[/tex]
Hence, 3 moles of HCl will give 1 mole of [tex]AlCl_3[/tex]. So, moles of HCl required to react with 10 moles of [tex]AlCl_{3}[/tex] is as follows.
[tex]1 mol AlCl_3 = 3 mol HCl\\10 mol AlCl_{3} = 3 \times 10 mol HCl\\= 30 mol HCl[/tex]
Thus, we can conclude that if you want to make 10 moles of [tex]AlCl_{3}[/tex] then 30 moles of HCl are required in the given reaction.
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