Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Reasoning A cone with radius 3 and height 10 has its radius tripled. How many times
greater is the volume of the larger cone than the smaller cone? Use pencil and paper.
Explain how the volume of the cone would change if the radius were divided by three.
The volume of the larger cone is times greater than the volume of the smaller
cone.

Sagot :

Answer:

9 times larger and 9 times smaller (it changes by the square of the change factor of the radius).

Step-by-step explanation:

the reason :

the formula of the volume of a cone is base area times height divided by 3.

and the base area is the area of a circle with radius r.

=> Vc = pi×r²×height / 3

now, when we multiply r by a factor, like in our examples here by 3 and also by 1/3, then this factor also gets squared in the calculation of that formula.

so, if the new radius is 3×r, then the formula looks like

Vc = pi×(3r)²×height / 3 = pi×9r²×height / 3

so, as you can see, when we triple the radius, we introduce the factor 9 (square of 3) into the volume, and therefore the volume increases by the factor 9.

similar, when we divide the radius by 3

Vc = pi×(r/3)²×height / 3 = pi×(r²/9)×height / 3

we introduce the factor 1/9 into the volume, and it decreases to 1/9th of its original size.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.