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Find the focus of the parabola whose equation is y=1/8 x^2

Sagot :

MrRoyal

Answer:

The focus is: [tex](0,2)[/tex]

Step-by-step explanation:

Given

[tex]y = \frac{1}{8}x^2[/tex]

Required

Determine the focus

The focus of a parabola

[tex](x- h)^2 = 4p(y - k)[/tex]

is:

[tex](h,k+p)[/tex]

So, we have:

[tex]y = \frac{1}{8}x^2[/tex]

Cross multiply

[tex]8y = x^2[/tex]

Rewrite as:

[tex]x^2 = 8y[/tex]

Rewrite as:

[tex](x - 0)^2 = 8(y - 0)[/tex]

Express 8 as 4 * 2

[tex](x - 0)^2 = 4 * 2(y - 0)[/tex]

By comparison with: [tex](x- h)^2 = 4p(y - k)[/tex]

[tex]h = 0[/tex]    [tex]p =2[/tex]     [tex]k = 0[/tex]

So, the focus [tex](h,k+p)[/tex] is:

[tex](h,k+p) = (0,0+2)[/tex]

[tex](h,k+p) = (0,2)[/tex]

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