ishudinthapa
Answered

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find the magnitude and direction of AB vector joining point A(9,12) and B(8,11)​

Sagot :

bhadelsimron19

Answer:

Step-by-step explanation:

x1=9  x2=8  y1=12  y2=11

=x2-x1

y2-y1

=8-91

1-12

=-1

-1

magintude =[tex]\sqrt{(xcomp)^2+(y comp)^2[/tex]

=[tex]\sqrt{(-1)^2+(-1)^2[/tex]

=[tex]\sqrt{1+1[/tex]

=[tex]\sqrt{2[/tex]

direction=y component/x component

tan=-1/-1

tan=1

[tex]tan^{-1}[/tex] 1=45

=45 degree

both x component and y component are negative so it lies on third quadrant.

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