breannacusmano
Answered

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determine the level in decibels of a sound that has an intensity I = 10^-6 watts/cm2​

Sagot :

whitneytr12

Answer:

The level in decibels is 100.

Step-by-step explanation:

The intensity level in decibels (β) can be found using the following equation:

[tex] \beta = 10log(\frac{I}{I_{0}}) [/tex]

Where:

I: is the intensity = 10⁻⁶ W/cm²

I₀: is the reference intensity = 10⁻¹² W/m²

First, we need to convert the unit of the given intensity from W/cm² to W/m².

[tex] I = 10^{-6} \frac{W}{cm^{2}}*\frac{(100 cm)^{2}}{1 m^{2}} = 10^{-2} W/m^{2} [/tex]

Hence, the level in decibels is:

[tex] \beta = 10log(\frac{10 ^{-2} W/m^{2}}{10^{-12} W/m^{2}}) = 100 dB [/tex]

Therefore, the level in decibels is 100.

I hope it helps you!

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