Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

You need to produce a set of cylindrical copper wire 3.5 m long that will have a

resistance of 0.125 Ω each. What will be the mass of each of these wires?

(ρ = 1.72X10-8 Ωm, density of copper = 8.9X103 kg/m3)​

Sagot :

Solution :

We know, resistance is given by :

[tex]R = \dfrac{\rho l}{A}[/tex]

[tex]A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2[/tex]

Now, we know mass of wire is given by :

[tex]Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram[/tex]

Hence, this is the required solution.

Cricetus

The mass of the wire will be "15.00 g".

Given:

  • Length of wire, l = 3.5 m
  • Resistance, R = 0.125 Ω

The resistance will be:

→ [tex]R = \frac{\rho l}{A}[/tex]

or,

→ [tex]A = \frac{\rho l}{R}[/tex]

By substituting the values, we get

      [tex]= \frac{1.72\times 10^{-8}\times 3.5}{0.125}[/tex]

      [tex]= 4.816\times 10^{-7} \ m^2[/tex]

hence,

The mass will be:

→ [tex]Mass = Density\times Volume[/tex]

             [tex]= 8.9\times 10^3\times 4.816\times 10^{-7}\times 3.5[/tex]

             [tex]= 0.01500 \ kg[/tex]

             [tex]= 15.00 \ g[/tex]

Thus the above answer is right.  

Learn more about mass here:

https://brainly.com/question/17108656

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.