Answered

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Does anyone know how to solve this?

Does Anyone Know How To Solve This class=

Sagot :

Given :

A right angle triangle ABC .

To Find :

The perimeter of ABC .

Solution :

Since, triangle ABC is right angled and angle ∠ABC is 46° .

So, AC = AB cos 46° = 7.64 units.

Also, CB = AB sin 46° = 7.91 units.

Therefore, the perimeter of ΔABC is :

P = 11 + 7.64 + 7.91 units

P = 26.55 units

Hence, this is the required solution.

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