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You roll a six-sided number cube and flip a coin. What is the probability of rolling a number less than 2 and flipping heads? Write your answer as a fraction in simplest form. The probability is .

Sagot :

Answer:

[tex]\frac{1}{18}[/tex]

Step-by-step explanation:

As the six-sided number cube had six sides, there are six events which could occur. There is only one interger less than 2 (1), therefore the probability of rolling a number less than 2 is [tex]\frac{1}{6}[/tex].

There are two events which could occur when flipping a coin. This means the probability of flipping heads is [tex]\frac{1}{2}[/tex].

To find the probability of both of these happening, you must multiply the fractions together by multiplying together both the denominators and numerators, therefore:

[tex]\frac{1}{6}[/tex] ×  [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{18}[/tex]

Answer:

1/12

Step-by-step explanation:

There is only one number less than two, which is 1, so you have 1/6 chance of getting a number less than two

Since a coin has two sides, you have 1/2, or 50% chance of landing on heads

If you multiply both of them, which is 1/6 times 1/2, you will get 1/12, since 1 times 1 is still 1, and 6 times 2 is 12.