Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Step-by-step explanation:
[tex]\theta[/tex] 0° 30° 45° 60° 90°
[tex]Sin \theta[/tex] [tex]0[/tex] [tex]\frac{1}{2}[/tex] [tex]\frac{\sqrt{2}}{2}[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] [tex]1[/tex]
[tex]Cos \theta[/tex] [tex]1[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] [tex]\frac{\sqrt{2} }{2}[/tex] [tex]\frac{1}{2}[/tex] [tex]0[/tex]
[tex]Tan \theta[/tex] [tex]0[/tex] [tex]\frac{1}{\sqrt{3} }[/tex] [tex]1[/tex] [tex]\sqrt{3}[/tex] ∞
Answer:
Step-by-step explanation:
sin A=opposite/hypotenuse
cos A=adjacent/hypotenuse
tan A=opposite/adjacent
cosec A=hypotenuse/opposite
sec A=hypotenuse/adjacent
tan A=adjacent/hypotenuse
Hope this helps u!!
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.