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Sagot :
Answer:
Step-by-step explanation:
[tex]\theta[/tex] 0° 30° 45° 60° 90°
[tex]Sin \theta[/tex] [tex]0[/tex] [tex]\frac{1}{2}[/tex] [tex]\frac{\sqrt{2}}{2}[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] [tex]1[/tex]
[tex]Cos \theta[/tex] [tex]1[/tex] [tex]\frac{\sqrt{3} }{2}[/tex] [tex]\frac{\sqrt{2} }{2}[/tex] [tex]\frac{1}{2}[/tex] [tex]0[/tex]
[tex]Tan \theta[/tex] [tex]0[/tex] [tex]\frac{1}{\sqrt{3} }[/tex] [tex]1[/tex] [tex]\sqrt{3}[/tex] ∞
Answer:
Step-by-step explanation:
sin A=opposite/hypotenuse
cos A=adjacent/hypotenuse
tan A=opposite/adjacent
cosec A=hypotenuse/opposite
sec A=hypotenuse/adjacent
tan A=adjacent/hypotenuse
Hope this helps u!!
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