alishaham606
Answered

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A ladder 17m long rests against a vertical wall. The foot of the ladder is 8m away from the base of the wall. How high up the wall will the ladder reach?

Sagot :

slm45

Answer:

So the high of the of the wall will be, 15m

Step-by-step explanation:

You can use Pythagoras theorem, c^2=a^2+b^2.

Take the length of the ladder as c, the foot of the ladder as (a), and the high of the wall as (b).

So :

c^2=a^2+b^2

(17m)^2= (8m)^2+ b^2

289m^2 = 64m^2 + b^2

289m^2 - 64m^2 = b^2

225m^2 = b^2

[tex] \sqrt{225m \:} = b[/tex]

15m = b

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