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Sagot :

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Given,

[tex]3x - 2y = 5[/tex]

[tex]xy = - 2[/tex]

Now,

[tex](3x - 2y) {}^{2} = (5) {}^{2} \\ [/tex]

Use the algebraic identity (a - b)² = a² - 2ab + b²

[tex](3x - 2y) {}^{2} = (5) {}^{2} \\ 3x {}^{2} - 2 \times 3x \times 2y + 2y {}^{2} = 5 {}^{2} \\ 9 {x}^{2} - 12xy + 4y {}^{2} = 25 \\9x {}^{2} + 4y {}^{2} = 25 + 12xy \\ 9x {}^{2} + 4 {y}^{2} - 1 = 24 + 12xy[/tex]

So, the value of 9x² + 4y² - 1 is 24 + 12xy

Now,

xy = - 2

So, 12xy = 12 × - 2 = - 24

•°• 24 + 12xy

= 24 + (-24)

= 24 - 24

= 0

The value of 9x² + 4y² - 1 is 0.

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