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The absolute value function g(x) = |x + 2| + 1 is translated 4 units right and 5 units up to become g'(x). The quadratic function f(x) graphed below is moved 5 units right and 2 units down to become f'(x). Which of these two transformed functions has a range of y ≤ −6, and what is the vertex of this transformed function?

Graph of the quadratic function f of x that comes up from the left through negative four comma negative eight to the turning point at negative two comma negative four and goes down through zero comma negative eight and continues toward negative infinity

g'(x) has a range of y ≤ −6, and its vertex is at (−6, 6).
g'(x) has a range of y ≤ −6, and its vertex is at (2, 6).
f'(x) has a range of y ≤ −6, and its vertex is at (3, −6).
f'(x) has a range of y ≤ −6, and its vertex is at (−7, −6).

Sagot :

Answer:

g'(x) has a range of y ≤ −6, and its vertex is at (−6, 6)

Step-by-step explanation:

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