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The difference of the square of a number and 18 is equal to 3 times that number. Find the positive solution.

Sagot :

Answer:

18 = 3 x 6

Step-by-step explanation:

If you don't know the difference of the square of a number you can already see that it's telling 18 = 3 times that number so identify the missing number by multiplying 3 times a number.

18 = 3 x ?

18 = 3 x 6

18 = 18

:D

Answer:

6

Step-by-step explanation:

Let us start by writing an equation using the variable x.

The square of a number x minus 18 equals 3 times x:

[tex]x^{2} -18=3x[/tex]

Great! Now let us solve for x by moving the 3x term to the left side of the equation and obtain a quadratic equation:

[tex]x^{2} -3x-18=0[/tex]

We can use the quadratic formula [tex]\frac{-b±\sqrt{b^{2}-4ac } }{2a}[/tex] to solve for x. *Please ignore the A after b. I cannot remove it for some reason.*

From our equation, a represents the coefficient of the term with degree of 2. Therefore, our a variable is 1. b represents the coefficient of the term with degree 1. Out variable b is therefore -3. Lastly, c represents the term with degree 0. Our c variable is -18. Lets solve!

[tex]\frac{3 ±\sqrt{(-3)^{2}-4*1*(-18) } }{2*1} =\\\frac{3 ±\sqrt{9+72} }{2} =\\\frac{3 ±\sqrt{81} }{2} =\\\frac{3 ±9}{2} \\\\[/tex]

Now we have two possible solutions. Let us start with the addition version:

[tex]\frac{3+9}{2} =\\\frac{12}{2} =\\6[/tex]

Alternatively you could try the subtraction version:

[tex]\frac{3-9}{2} =\\\frac{-6}{2} =\\-12[/tex]

However, the question asks to find the positive solution. Therefore, out answer is 6.

I hope this helps! Please let me know if you have any questions :)

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