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Sagot :
The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of [tex]N_2[/tex] in 10.58 L of nitrogen gas
(b): Calculate the grams of [tex]N_2[/tex] in [tex]5.03\times 10^{20}[/tex] moles of nitrogen gas
(c): Calculate the moles of [tex]N_2[/tex] molecules in 3.94 grams of nitrogen gas
(d): Calculate the moles of [tex]N_2[/tex] molecules in 4.73 L of nitrogen gas
Answer: The correct options are (b) and (c).
Explanation:
We are given:
Molar mass of [tex]N_2[/tex] = 28.02 g/mol
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
At STP conditions:
1 mole of gas occupies 22.4 L of volume
For the given options:
(a): Volume is given and to calculate the mass of [tex]N_2[/tex], we need to use both the conversion factors above.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex]\frac{1mol}{22.4L}\times 10.58L\times 28.02 g/mol[/tex]
(b): Moles are given and to calculate the mass of [tex]N_2[/tex], we need only the first conversion factor.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex](5.03\times 10^{20}mol)\times 28.02g/mol[/tex]
(c): Mass is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the first conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{3.94 g}{28.02g/mol}[/tex]
(d): Volume is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the second conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{1mol}{22.4L}\times 4.73L[/tex]
Hence, the correct option is (b) and (c)
Using only 28.02 g/mol as a conversion factor, we can:
- (b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
- (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
We want to identify the conversion factors required in a series of calculations.
What is a conversion factor?
A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
28.02 g/mol, which is the molar mass of nitrogen, is a conversion factor to convert moles to mass and vice versa.
- (a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.
We want to convert 10.58 L (volume) to grams (mass). We need to conversion factors:
- 22.4 L/mol is the conversion factor to convert volume to moles.
- 28.02 g/mol is the conversion factor to convert moles to mass.
- (b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
We want to convert 5.03 × 10²⁰ moles (moles) to grams (mass). We can do so by just using 28.02 g/mol as the conversion factor.
- (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
We want to convert 3.94 grams (mass) to moles. We can do so by just using 28.02 g/mol as the conversion factor.
- (d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.
We want to convert 4.73 L (volume) to moles. The required conversion factor is 22.4 L/mol.
Using only 28.02 g/mol as a conversion factor, we can:
- (b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
- (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
(c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
(d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.
Learn more about conversion factors here: https://brainly.com/question/97386
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