Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 8 feet. Container B has a diameter of 12 feet and a height of 7 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

Sagot :

reinhard10158

Answer:

79.4 %

Step-by-step explanation:

volume of cylinder : pi×r²×h

attention ! the question gives us the diameters, so for the radius, we need to cut them in half.

Va = pi × (10/2)² × 8 = pi×25×8 = 628.31853... ft³

Vb = pi × (12/2)² × 7 = pi×36×7 = 791.68135... ft³

100% Vb = 791.68135... ft³

1% Vb = 7.9168135... ft³

now, 628.31853... ft³ have been pumped into B.

so, how often does 1% of the volume of B fit into that filled volume ?

628.31853... / 7.9168135... = 79.36507937...% = 79.4%

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.