carlygracevu
Answered

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Sagot :

leena

Hi there!

[tex]\large\boxed{\text{33 in}^2}[/tex]

Find the total area by breaking the figure into two rectangles, one trapezoid, and one triangle.

Rectangles:

A = l × w

A = 2.75 × 4 = 11 in²

Solve for the other rectangle's length by subtracting from the total:

12 - 2 - 3 - 4 = 3

A = 3 × 3 = 9 in²

Total rectangle area: 11 + 9 = 20 in²

Trapezoid:

A = 1/2(b1 + b2)h

A = 1/2(4.25 + 2.75)3 = 21/2 = 10.5 in²

Triangle:

A = 1/2(bh)

A = 1/2(2.5 · 2) = 2.5 in²

Add up all of the areas:

20 + 10.5 + 2.5 = 33 in²

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