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What is an equation of the line that passes through the points (6, -3)and (−6,−5)?

Sagot :

wegnerkolmp2741o

Answer:

y = 1/6x -4

Step-by-step explanation:

First find the slope

m= ( y2-y1)/(x2-x1)

m=(-5 - -3)/( -6 -6)

   = (-5+3)/ (-6-6)

       = -2/-12

       = 1/6

The slope intercept form is

y= mx+b where m is the slope and b is the y intercept

y = 1/6 x +b

Substitute a point into the equation

-5 = 1/6(-6) +b

-5 = -1+b

Add 1 to each side

-4 = b

y = 1/6x -4

Answer:

y=1/6x-4

Step-by-step explanation:

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