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vertical gate in an irrigation canal holds back 12.2 m of water. Find the average force on the gate if its width is 3.60 m. Report your answer with proper units and 3 sig figs.

Sagot :

Answer:

The right solution is "2625 kN".

Explanation:

According to the question,

The average pressure will be:

= [tex]density\times g\times \frac{h}{2}[/tex]

By putting values, we get

= [tex]1000\times 9.8\times \frac{12.2}{2}[/tex]

= [tex]1000\times 9.8\times 6.1[/tex]

= [tex]59780[/tex]

hence,

The average force will be:

= [tex]Pressure\times Area[/tex]

= [tex]59780\times 3.6\times 12.2[/tex]

= [tex]2625537 \ N[/tex]

Or,

= [tex]2625 \ kN[/tex]

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