amartin1487
Answered

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Sagot :

Answer:

[tex]\sqrt{13}[/tex]

Step-by-step explanation:

Given a vector < x, y > then its magnitude is

[tex]\sqrt{x^2+y^2}[/tex]

Given the directed line segment

P (0, 0 ) → Q (3, 2 ) then

PQ = q - p = (3, 2 ) - (0, 0 ) = < 3 - 0, 2 - 0 > = < 3 , 2 >

| PQ | = [tex]\sqrt{3^2+2^2}[/tex] = [tex]\sqrt{9+4}[/tex] = [tex]\sqrt{13}[/tex]

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