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What are the roots of the equation x^2+8x+32=0 in simplest a+bi form?

Sagot :

altavistard

Answer:

x =  -4 ± i4

Step-by-step explanation:

This is a quadratic equation with coefficients {1, 8, 32}.  We apply the quadratic formula to solve for x.  The first step is to find the 'discriminant,' b^2 - 4 ac, which here is (8)^2 - 4(1)(32), or 64 - 128, or -64.  

A negative discriminant indicates that this quadratic has two unequal complex roots.  

                               -b ± √(b^2 - 4ac)

The formula is x = ----------------------------

                                         2a

which, when evaluated at a = 1, b = 8 and c= 32, yields

                               -8 ± √(-64)

The formula is x = ----------------------------

                                         2(1)

or:

                               -8 ± i√64                

The formula is x = -----------------   = x =  -4 ± i4

                                        2

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