farnelxd
Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What are the roots of the equation x^2+8x+32=0 in simplest a+bi form?

Sagot :

altavistard

Answer:

x =  -4 ± i4

Step-by-step explanation:

This is a quadratic equation with coefficients {1, 8, 32}.  We apply the quadratic formula to solve for x.  The first step is to find the 'discriminant,' b^2 - 4 ac, which here is (8)^2 - 4(1)(32), or 64 - 128, or -64.  

A negative discriminant indicates that this quadratic has two unequal complex roots.  

                               -b ± √(b^2 - 4ac)

The formula is x = ----------------------------

                                         2a

which, when evaluated at a = 1, b = 8 and c= 32, yields

                               -8 ± √(-64)

The formula is x = ----------------------------

                                         2(1)

or:

                               -8 ± i√64                

The formula is x = -----------------   = x =  -4 ± i4

                                        2

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.