Answered

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If f(1)=4f(1)=4 and f(n)=f(n-1)^2+2f(n)=f(nāˆ’1)
2
+2 then find the value of f(3)f(3).

Sagot :

abidemiokin

Answer:

f(3) = 326

Step-by-step explanation:

Given the function

f(n)=f(n-1)^2+2

If f(1) = 4

f(2) = f(1)^2 + 2

f(2) = 4^2 + 2

f(2) = 16 + 2

f(2) = 18

f(3) = f(2)^2 + 2

f(3) = 18^2 + 2

f(3) = 324 + 2

f(3) = 326

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