Answer:
Step-by-step explanation:
We see that if we do a direct substitution for x as 1 we have a 0 in the denominator, which is a big no-no. So we try to manipulate the function so that doesn't happen. We can factor the numerator. When we do that we get
[tex]\lim_{x \to 1} \frac{(x-1)(x^2+x+1)}{(x-1)}[/tex] The (x-1) terms cancel out leaving us with just
[tex]\lim_{x \to 1} (x^2+x+1)[/tex] which is no longer a problem! This limit is found by subbing in a 1 for x and doing the math. The limit is 3.
