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What is the center of the circle (x+7)^2+(y+4)^2=25

Sagot :

sqdancefan

9514 1404 393

Answer:

  (-7, -4)

Step-by-step explanation:

Compare the given equation to the standard form equation for a circle with center (h, k) and radius r.

  (x -h)^2 +(y -k)^2 = r^2

You see that ...

  -h = +7   ⇒   h = -7

  -k = +4   ⇒   k = -4

Then the center is ...

  (h, k) = (-7, -4)

__

The radius is ...

  r^2 = 25   ⇒   r = √25 = 5 . . . radius of the circle

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