Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

I’m failing I really need help please!

Im Failing I Really Need Help Please class=

Sagot :

samuelthankgod

Answer:

3 and -4

Step-by-step explanation:

this is simple but difficult

let the number be x and second number be y

3x + 2y=1

x-y/2=5

from the 2nd equation

x-y/2=5

x=5+y/2

substitute value for x into equation 1

3x + 2y=1

3(5+y/2) + 2y= 1

15 +3y/2 +2y=1

15 + 7y/2=1

7y/2= 1 - 15

7y/2=-14

cross multiply

7y= -28

y= -28/7

y= -4

therefore second number is -4

substitute value for y into 1st equation

3x + 2y=1

3x + 2(-4) = 1

3x - 8= 1

3x= 1+8

3x= 9

x= 9/3

x= 3

therefore first number is 3

therefore two numbers are;

3 and -4

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.