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when a constant force is applied to an object, the acceleration of the object varies Inversely with its mass. When a certain constant force acts upon an object with mass 22 kg, the acceleration of the object is 2 m/s². When the same force acts upon another object, its acceleration is 11 m/s? What is the mass of this object? ​

Sagot :

Answer:

The mass of the object is 4 kilograms.

Explanation:

From the Second Newton's Law, under the same force, we know that the mass of the object is inversely proportional to the acceleration experimented by the object:

[tex]m_{1}\cdot a_{1} = m_{2}\cdot a_{2}[/tex] (1)

Where:

[tex]m_{1}[/tex], [tex]m_{2}[/tex] - Masses, in kilograms.

[tex]a_{1}, a_{2}[/tex] - Accelerations, in meters per square second.

If we know that [tex]m_{1} = 22\,kg[/tex], [tex]a_{1} = 2\,\frac{m}{s^{2}}[/tex] and [tex]a_{2} = 11\,\frac{m}{s^{2}}[/tex], then the resulting mass is:

[tex]m_{2} = m_{1} \cdot \left(\frac{a_{1}}{a_{2}} \right)[/tex]

[tex]m_{2} = (22\,kg)\cdot \left(\frac{2\,\frac{m}{s^{2}} }{11\,\frac{m}{s^{2}} } \right)[/tex]

[tex]m_{2} = 4\,kg[/tex]

The mass of the object is 4 kilograms.

The mass of the object will be "4 kg".

Given values,

Mass,

  • [tex]m_1 = 22 \ kg[/tex]
  • [tex]m_2 = \ ?[/tex]

Acceleration,

  • [tex]a_1 = 2 \ m/s^2[/tex]
  • [tex]a_2 = 11 \ m/s^2[/tex]

As we know,

→ [tex]m_1 . a_1 = m_2.a_2[/tex]

or,

→     [tex]m_2 = m_1 . (\frac{a_1}{a_2} )[/tex]

By putting the values, we get

            [tex]= 22\times (\frac{2}{11} )[/tex]

            [tex]= 4 \ kg[/tex]

Thus the above approach is right.

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