Answered

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What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g

Sagot :

okpalawalter8

Answer:

[tex]V'=1040ml[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=10.5mL[/tex]

Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]

Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]

Generally the equation for Acidity &Volume Relationship is mathematically given by

[tex]N_1V_1=N_2V_2[/tex]

Therefore

[tex]V_2=\frac{N_1V_2}{N_2}[/tex]

[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]

Therefore

Change in Water volume is

[tex]V'=V_2-V_1[/tex]

[tex]V'=1050ml-10ml[/tex]

[tex]V'=1040ml[/tex]

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