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Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.

Need Help ASAP I Forgot All The Steps After The Area Is Solved With 5 Or If 25pi Is The Right Answer class=

Sagot :

Corsaquix

Answer:

[tex]42.5\:\mathrm{m^2}[/tex]

Step-by-step explanation:

The area of a sector with measure [tex]\theta[/tex] in degrees is given by [tex]r^2\pi\cdot\frac{\theta}{360}[/tex], where [tex]r[/tex] is the radius of the sector.

What we're given:

  • [tex]r[/tex] of 5
  • [tex]\theta[/tex] of [tex]195^{\circ}[/tex]

Solving, we get:

[tex]A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}[/tex]

*Notes:

  • units should be in square meters (area)
  • the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants
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