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special right triangles (radical answers)


Help Please NO LINKS Special Right Triangles Radical Answers class=

Sagot :

MrMyth
The answer is 6 root 2

Answer:

x = [tex]\sqrt{6}[/tex]

Step-by-step explanation:

Since the given triangle is equilateral the all 3 sides would be:

[tex]\sqrt{6} +\sqrt{6}[/tex] or [tex]\sqrt{12}[/tex]. Now we know that the base of the right triangle is [tex]\sqrt{6}[/tex] and the hypotenuse is [tex]\sqrt{12}[/tex]. Therefore we can say;

A² + B² = C²

([tex]\sqrt{6}[/tex])² + x² = ([tex]\sqrt{12}[/tex])²

6 + x² = 12

x² = 12 - 6

x² = 6

x = [tex]\sqrt{6}[/tex]

Therefore; x = [tex]\sqrt{6}[/tex] is the length of x, in simplest radical form.