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Sagot :
13. $25/month
14. 36 and 37
Step-by-step explanation:
Let a = monthly rate ($/month)
t = time (months)
k = installation cost
The equation for the cost of the internet service C is
C = at + k
Since C = $685. t = 24 months (2 years) and k = $85, we can solve for a:
at = C - k
or
a = (C - k)/t
= ($685 - $85)/(24 months)
= $25/month
14. Let n = the number
n + 1 = the number after n
Since the sum of two consecutive numbers is 73, we can write the equation as
n + (n + 1) = 73
which simplifies to
2n + 1 = 73
2n = 72
Solving for n, we find that
n = 36
so the other number is 36 + 1 = 37.
Answer For The First Question:
25
Here's why:
Note that the cost corresponds to 2 years of service. Also, the problem asks for the one-month fee. Then, a good start would be saying: OK, the cost of 24 months of service was $685, including the installation fee. Since this fee is a one-time cost, not a monthly cost, we need to subtract it from our total cost. Then the cost of the service minus the installation fee could be written as:
24x = 685 - 85
That is 24 months of service, at x cost per month, is equal to 685 minus 85.
If you solve this equation, you will find the value of x:
24x = 600
x = 600 ÷ 24
x = 25
The monthly fee is $25. In 2 years you paid 24 times 25, or $600. Add to this amount the installation fee of $85 and you will arrive at your total cost, which includes the installation fee.
Second Answer:
36 and 37
Here's why:
36+37=73
You can solve this by first dividing 73 by 2.
73/2 = 36.5
Next, take .5 away from one of the 36.5 and give it to the other one. That gives us an answer of 36 and 37.
I hope this helps! If you are confused about anything, let me know :)
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