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A 45 gram sample of a substance that's used to sterilize surgical equipment has a
K-value of 0.1483.
Find the substance's half-life, in days. Round your answer to the nearest tenth.
Answer:

Sagot :

wegnerkolmp2741o

Answer:

t = 4.7 days

Step-by-step explanation:

The half life formula is

N = No * e ^ (-kt)

Where No is the initial amount of the substance

N = 45 e ^ (-.1483 t)

We want 1/2 of the substance left

22.5 is half of 45 grams

22.5 = 45 e ^ (-.1483 t)

Divide each side by 45

1/2 = e ^ (-.1483 t)

Take the natural log of each side

ln(1/2) = ln (e ^ (-.1483 t))

ln(1/2) = -.1483t

Divide each side by -.1483

ln(1/2) / -.1483 = t

t=4.67395

Rounding to the nearest tenth

t = 4.7 days

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